用dos命令获取系统时间的实例代码

发布时间:2020-03-16编辑:脚本学堂
本文介绍下,在windows中用dos命令获取当前系统时间的例子,主要用到了一些时间变量,初学dos命令的朋友不妨参考下。

dos命令取得当前系统时间,代码如下:
 

复制代码 代码示例:
rem DOS get current time
rem -------------------
rem get yyyy/mm/dd
set mydate=%DATE:~0,10%
echo %mydate%
rem -------------------
rem get yyyy
set yyyy=%DATE:~0,4%
echo %yyyy%
rem -------------------
rem get mm
set mm=%DATE:~5,2%
echo %mm%
rem -------------------
rem get dd
set dd=%DATE:~8,2%
echo %dd%
rem -------------------
rem get yyyy-mm-dd
set curdate=%yyyy%-%mm%-%dd%
echo %curdate%

说明:bat中获取时间,可以理解为截取日期中字符串的方法。

用dos命令处理字符串的方法,
例如,日期:”2013-07-22 星期一”, 这个%DATE:~0,10%得到的是2013-07-22
说明:DATE为系统变量,“:”表示开始处理前面的字符串“~0,10”表示从第0个字符开始取10个字符。

以上代码的输出结果:
 

C:Documents and SettingsAdministrator>rem DOS get current time
C:Documents and SettingsAdministrator>rem -------------------
C:Documents and SettingsAdministrator>rem get yyyy/mm/dd
C:Documents and SettingsAdministrator>set mydate=2013-07-22
C:Documents and SettingsAdministrator>echo 2013-07-22
2013-07-22
C:Documents and SettingsAdministrator>rem -------------------
C:Documents and SettingsAdministrator>rem get yyyy
C:Documents and SettingsAdministrator>set yyyy=2013
C:Documents and SettingsAdministrator>echo 2013
2013
C:Documents and SettingsAdministrator>rem -------------------
C:Documents and SettingsAdministrator>rem get mm
C:Documents and SettingsAdministrator>set mm=07
C:Documents and SettingsAdministrator>echo 07
07
C:Documents and SettingsAdministrator>rem -------------------
C:Documents and SettingsAdministrator>rem get dd
C:Documents and SettingsAdministrator>set dd=22
C:Documents and SettingsAdministrator>echo 22
22
C:Documents and SettingsAdministrator>rem -------------------
C:Documents and SettingsAdministrator>rem get yyyy-mm-dd
C:Documents and SettingsAdministrator>set curdate=2013  -07  -22
C:Documents and SettingsAdministrator>echo 2013  -07  -22
2013  -07  -22
C:Documents and SettingsAdministrator>